Trabajo dia 6 dic

169 days ago by karencepeda@tecpabellon

#1 u = matrix([[1,0,0,0],[0,1,0,0],[0,0,1,0]]) u.echelon_form() 
        
[1 0 0 0]
[0 1 0 0]
[0 0 1 0]
[1 0 0 0]
[0 1 0 0]
[0 0 1 0]
var('k1,k2,k3') eqn = [1*k1+0*k2+3*k3==0, 0*k1+1*k2+0*k3==0, 0*k1+2*k2-1*k3==0] s = solve(eqn, k1,k2,k3); s 
        
[[k1 == 0, k2 == 0, k3 == 0]]
[[k1 == 0, k2 == 0, k3 == 0]]
w = matrix([[1,0,0],[0,1,0],[0,0,1]]) w.determinant() 
        
1
1
ES INDEPENDIENTE POR LO TANTO SI CUMPLE CON LA BASE PARA R3 
       
#2 u = matrix([[1,1,0,0],[-1,0,0,0]]) u.echelon_form() 
        
[1 0 0 0]
[0 1 0 0]
[1 0 0 0]
[0 1 0 0]
var('k1,k2,k3') eqn = [1*k1+0*k2+3*k3==0, -1*k1+1*k2+0*k3==0, 0*k1+2*k2-1*k3==0] s = solve(eqn, k1,k2,k3); s 
        
[[k1 == 0, k2 == 0, k3 == 0]]
[[k1 == 0, k2 == 0, k3 == 0]]
w = matrix([[1,1,0],[-1,0,0]]) w.determinant() 
        
Traceback (click to the left of this block for traceback)
...
ValueError: self must be a square matrix
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "_sage_input_9.py", line 10, in <module>
    exec compile(u'open("___code___.py","w").write("# -*- coding: utf-8 -*-\\n" + _support_.preparse_worksheet_cell(base64.b64decode("dyA9IG1hdHJpeChbWzEsMSwwXSxbLTEsMCwwXV0pCncuZGV0ZXJtaW5hbnQoKQ=="),globals())+"\\n"); execfile(os.path.abspath("___code___.py"))
  File "", line 1, in <module>
    
  File "/tmp/tmp14cud7/___code___.py", line 4, in <module>
    exec compile(u'w.determinant()
  File "", line 1, in <module>
    
  File "matrix_integer_dense.pyx", line 3228, in sage.matrix.matrix_integer_dense.Matrix_integer_dense.determinant (sage/matrix/matrix_integer_dense.c:24519)
ValueError: self must be a square matrix
NO SE TIENE RESULTADO PUESTO QUE LA MATRIZ NO ES CUADRATICA 
       
#3 u = matrix([[1,-1,1,0],[-1,2,-2,0],[-1,4,-4,0]]) u.echelon_form() 
        
[ 1  0  0  0]
[ 0  1 -1  0]
[ 0  0  0  0]
[ 1  0  0  0]
[ 0  1 -1  0]
[ 0  0  0  0]
var('k1,k2,k3') eqn = [1*k1+0*k2+3*k3==0, -1*k1+1*k2+0*k3==0, -1*k1+2*k2-1*k3==0] s = solve(eqn, k1,k2,k3); s 
        
[[k1 == 0, k2 == 0, k3 == 0]]
[[k1 == 0, k2 == 0, k3 == 0]]
w = matrix([[1,-1,1],[-1,2,-2],[-1,4,-4]]) w.determinant() 
        
0
0
ES DEPENDIENTE POR LO TANTO NO EXISTE BASE PARA R3