Fermat 27 output (etiquette?)

277 days ago by b0yscout

num = 27 ind_count =[25,24,23,22,21,20,19,18,17,16,15,14,13,12,11,10,9,8,7,6,5,4,3,2,1] count = 0 fermat = (2^(2^num))+1 n = fermat%10^10000000 fermat = fermat - n fermat = fermat / 10^10000000 o = open('f_dat_end','w') o.write(str(n)) o.close() while (fermat > 10^10000000): n=fermat%10^10000000 count = count + 1 n_count = ind_count[count] chomp = str(n_count) nomdeplume = ('f_dat' + chomp) o = open(nomdeplume,'w') o.write(str(n)) o.close() fermat = fermat - n fermat = fermat / 10^10000000 o = open ('first_part', 'w') o.write(str(fermat)) o.close() print print "done"