integral tarea 1

309 days ago by 1234christian5689@tecpabellon

f=((x)^4+3*(x)-9) f.integral(x) 
        
1/5*x^5 + 3/2*x^2 - 9*x
1/5*x^5 + 3/2*x^2 - 9*x
f=(4*x-(2*(x)^(-1/3))+5/(x^2)) f.integral(x) 
        
2*x^2 - 3*x^(2/3) - 5/x
2*x^2 - 3*x^(2/3) - 5/x
f=((x)^8+x^-8) f.integral(x) 
        
1/9*x^9 - 1/7/x^7
1/9*x^9 - 1/7/x^7
f=(3*x^(3/4)+7*x^-5+6*x^(1/2)) f.integral(x) 
        
12/7*x^(7/4) + 4*x^(3/2) - 7/4/x^4
12/7*x^(7/4) + 4*x^(3/2) - 7/4/x^4
f=((4*x+1)^2) f.integral(x) 
        
16/3*x^3 + 4*x^2 + x
16/3*x^3 + 4*x^2 + x
f=(5*x^(-3/2)+2*x^(-2/3)) f.integral(x) 
        
6*x^(1/3) - 10/sqrt(x)
6*x^(1/3) - 10/sqrt(x)
f=(3*x^(1/2)) f.integral(x) 
        
2*x^(3/2)
2*x^(3/2)
f=((5*x+1)^(1/2)) f.integral(x) 
        
2/15*(5*x + 1)^(3/2)
2/15*(5*x + 1)^(3/2)
f=(3*x^(1/2)) f.integral(x) 
        
2*x^(3/2)
2*x^(3/2)
F=((4*x^2+3)^-6) f.integral(x) 
        
2*x^(3/2)
2*x^(3/2)
f=((5-3*x^2)^-2) f.integral(x) 
        
-1/300*sqrt(15)*log((3*x - sqrt(15))/(3*x + sqrt(15))) - 1/10*x/(3*x^2 -
5)
-1/300*sqrt(15)*log((3*x - sqrt(15))/(3*x + sqrt(15))) - 1/10*x/(3*x^2 - 5)
#Me faltaron dos del exámen. 
       
var('z') f=(z) f.integral(z,0,1) 
        
1/2
1/2